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Shelby Township, Ripley County, Indiana

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CountryUnited States
Elevation912 ft (278 m)
FIPS code18-69264[2]
Shelby Township
Coordinates: 38°58′19″N 85°22′34″W / 38.97194°N 85.37611°W / 38.97194; -85.37611
CountryUnited States
StateIndiana
CountyRipley
Government
 • TypeIndiana township
Area
 • Total
69.39 sq mi (179.7 km2)
 • Land69.11 sq mi (179.0 km2)
 • Water0.27 sq mi (0.70 km2)
Elevation912 ft (278 m)
Population
 (2020)
 • Total
1,038
 • Density15.02/sq mi (5.799/km2)
Area code812
FIPS code18-69264[2]
GNIS feature ID453845

Shelby Township is one of eleven townships in Ripley County, Indiana. As of the 2020 census, its population was 1,038 (up from 999 at 2010[3]) and it contained 373 housing units.[4]

Historical population
CensusPop.Note%±
18902,365—
19002,3870.9%
19102,182−8.6%
19201,995−8.6%
19301,569−21.4%
19401,6656.1%
1950801−51.9%
196088110.0%
1970830−5.8%
19809018.6%
1990853−5.3%
20008671.6%
201099915.2%
20201,0383.9%
Source: US Decennial Census[5]

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