Horoghiuca
River in Botoșani County, Romania
From Wikipedia, the free encyclopedia
The Horoghiuca is a right tributary of the river Miletin in Romania.[1][2] It flows into the Miletin in Coșula. Its length is 10 km (6.2 mi) and its basin size is 86 km2 (33 sq mi).[2]
| Horoghiuca | |
|---|---|
  Location within Romania | |
| Location | |
| Country | Romania |
| Counties | Botoșani County |
| Villages | Pădureni |
| Physical characteristics | |
| Mouth | Miletin |
• coordinates | 47.6201°N 26.7812°E |
| Length | 10 km (6.2 mi) |
Basin size | 86 km2 (33 sq mi) |
| Discharge | |
| • location | * |
| • minimum | 0 m3/s (0 cu ft/s) |
| • maximum | 17.20 m3/s (607 cu ft/s) |
| Basin features | |
| Progression |
Prut→ Danube→ Black Sea |
| Tributaries | |
| • left | Pârâul Mare, Prisaca |
River code | XIII.1.15.25.3 |
