Huron, Indiana
Census-designated place in Indiana, United States
From Wikipedia, the free encyclopedia
Huron is a Census-designated place in Spice Valley Township, Lawrence County, in the U.S. state of Indiana.[1]
Huron, Indiana | |
|---|---|
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  Huron  Huron | |
| Coordinates: 38°43′16″N 86°40′15″W | |
| Country | United States |
| State | Indiana |
| County | Lawrence |
| Township | Spice Valley |
| Elevation | 564 ft (172 m) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 47446 |
| Area code | 812 |
| GNIS feature ID | 2830451[1] |
History
Huron was platted in 1859.[2] It was named after Huron, Ohio.[3] On September 16, 1861, during the American Civil War, a train carrying 600 Illinois Union soldiers crashed into a creek near Huron, killing or injuring 100-150 soldiers.[4]
Demographics
The United States Census Bureau delineated Huron as a census designated place in the 2022 American Community Survey.[5]
