Iridium tetrafluoride
Chemical compound
From Wikipedia, the free encyclopedia
Iridium(IV) fluoride is a chemical compound of iridium and fluorine, with the chemical formula IrF4 and is a dark brown solid.[1] Early reports of IrF4 prior to 1965 are questionable and appear to describe the compound IrF5.[1] The solid can be prepared by reduction of IrF5 with iridium black[1] or reduction with H2 in aqueous HF.[2] The crystal structure of the solid is notable as it was the first example of a three-dimensional lattice structure found for a metal tetrafluoride and subsequently RhF4, PdF4 and PtF4 have been found to have the same structure.[3] The structure has 6 coordinate, octahedral, iridium where two edges of the octahedra are shared and the two unshared fluorine atoms are cis to one another.[3]
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| Names | |
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| Other names
Iridium tetrafluoride | |
| Identifiers | |
3D model (JSmol) |
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| ChemSpider | |
PubChem CID |
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| Properties | |
| IrF4 | |
| Molar mass | 268.2109 g/mol |
| Appearance | dark brown solid |
| Related compounds | |
Other anions |
Iridium dioxide |
Other cations |
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Related compounds |
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Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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