Rutland Township, Humboldt County, Iowa
From Wikipedia, the free encyclopedia
Rutland Township | |
|---|---|
 Location in Humboldt County | |
| Coordinates: 42°40′17″N 94°00′19″W / 42.67139°N 94.00528°W | |
| Country |  United States |
| State |  Iowa |
| County | Humboldt |
| Established | 1867 |
| Area | |
• Total | 34.8 sq mi (90 km2) |
| • Land | 34.5 sq mi (89 km2) |
| • Water | 0.3 sq mi (0.78 km2) |
| Elevation | 1,152 ft (351 m) |
| Population (2000) | |
• Total | 529 |
| • Density | 15/sq mi (5.8/km2) |
| Time zone | UTC-6 (CST) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP codes | 50582 (Rutland) |
| GNIS feature ID | 0468648 |
Rutland Township is one of twelve townships in Humboldt County, Iowa, United States.[1] As of the 2000 census, its population was 529.
Rutland Township was organized in 1867.[2]
Geography
According to the United States Census Bureau, Rutland Township covers an area of 34.8 square miles (90 km2); 34.5 square miles (89 km2) of this is land, and the remaining 0.3 square miles (0.78 km2) is water.
Cities, towns, villages
Adjacent townships
- Delana Township (north)
- Humboldt Township (northeast)
- Grove Township (east)
- Beaver Township (southeast)
- Corinth Township (south)
- Weaver Township (southwest)
- Avery Township (west)
- Wacousta Township (northwest)
Cemeteries
The township contains Rutland Township Cemetery.
