Vernon Township, Humboldt County, Iowa
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Vernon Township | |
|---|---|
 Location in Humboldt County | |
| Coordinates: 42°51′53″N 94°01′38″W / 42.86472°N 94.02722°W | |
| Country |  United States |
| State |  Iowa |
| County | Humboldt |
| Established | 1865 |
| Area | |
• Total | 36.5 sq mi (95 km2) |
| • Land | 36.5 sq mi (95 km2) |
| • Water | 0.0 sq mi (0 km2) |
| Elevation | 1,135 ft (346 m) |
| Population (2000) | |
• Total | 530 |
| • Density | 15/sq mi (5.8/km2) |
| Time zone | UTC-6 (CST) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP codes | |
| GNIS feature ID | 0468862 |
Vernon Township is one of twelve townships in Humboldt County, Iowa, United States.[1] As of the 2000 census, its population was 530.
Cities, towns, villages
According to the United States Census Bureau, Vernon Township covers an area of 36.5 square miles (95 km2); all of this land.
Adjacent townships
- Lu Verne Township, Kossuth County (north)
- Magor Township, Hancock County (northeast)
- Boone Township, Wright County (east)
- Liberty Township, Wright County (southeast)
- Lake Township (south)
- Grove Township (southwest)
- Humboldt Township (west)
- Sherman Township, Kossuth County (northwest)
Political districts
- Iowa's 4th congressional district
- State House District 4
