Seward Township, Winnebago County, Illinois

From Wikipedia, the free encyclopedia

CountryUnited States
EstablishedNovember 6, 1849 (1849-11-06)
Elevation
853 ft (260 m)
Seward Township
Township
Combined township building and fire station
Combined township building and fire station
Location in Winnebago County
Location in Winnebago County
Coordinates: 42°14′45″N 89°20′19″W / 42.24583°N 89.33861°W / 42.24583; -89.33861
CountryUnited States
StateIllinois
CountyWinnebago
EstablishedNovember 6, 1849 (1849-11-06)
Government
  SupervisorGarelt S. Stahl
Area
  Total
35.82 sq mi (92.8 km2)
  Land35.81 sq mi (92.7 km2)
  Water0 sq mi (0 km2)  0%
Elevation
853 ft (260 m)
Population
 (2010)
  Estimate 
(2016)[1]
889
  Density25.6/sq mi (9.9/km2)
Time zoneUTC-6 (CST)
  Summer (DST)UTC-5 (CDT)
FIPS code17-201-68783
[2][3]

Seward Township is located in Winnebago County, Illinois. As of the 2010 census, its population was 917 and it contained 394 housing units.[4]

According to the 2010 census, the township has a total area of 35.82 square miles (92.8 km2), all land.[4]

Demographics

References

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