Somerset, Indiana
From Wikipedia, the free encyclopedia
Somerset, Indiana | |
|---|---|
 | |
 Location of Somerset in Wabash County, Indiana. | |
| Coordinates: 40°40′10″N 85°49′53″W / 40.66944°N 85.83139°W | |
| Country | United States |
| State | Indiana |
| County | Wabash |
| Township | Waltz |
| Area | |
• Total | 0.82 sq mi (2.13 km2) |
| • Land | 0.68 sq mi (1.76 km2) |
| • Water | 0.14 sq mi (0.37 km2) |
| Elevation | 787 ft (240 m) |
| Population (2020) | |
• Total | 385 |
| • Density | 565.6/sq mi (218.39/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 46940 |
| FIPS code | 18-70524[3] |
| GNIS feature ID | 2631626[2] |
Somerset is an unincorporated census-designated place in Waltz Township, Wabash County, in the U.S. state of Indiana.[2] As of the 2020 census, Somerset had a population of 385.[4]
