Weak operator topology

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In functional analysis, the weak operator topology, often abbreviated WOT,[1] is the weakest topology on the set of bounded operators on a Hilbert space , such that the functional sending an operator to the complex number is continuous for any vectors and in the Hilbert space.

Explicitly, for an operator there is base of neighborhoods of the following type: choose a finite number of vectors , continuous functionals , and positive real constants indexed by the same finite set . An operator lies in the neighborhood if and only if for all .

Equivalently, a net of bounded operators converges to in WOT if for all and , the net converges to .

Strong operator topology

The WOT is the weakest among all common topologies on , the bounded operators on a Hilbert space .

The strong operator topology, or SOT, on is the topology of pointwise convergence. Because the inner product is a continuous function, the SOT is stronger than WOT. The following example shows that this inclusion is strict. Let and consider the sequence of right shifts. An application of Cauchy-Schwarz shows that in WOT. But clearly does not converge to in SOT.

The linear functionals on the set of bounded operators on a Hilbert space that are continuous in the strong operator topology are precisely those that are continuous in the WOT (actually, the WOT is the weakest operator topology that leaves continuous all strongly continuous linear functionals on the set of bounded operators on the Hilbert space H). Because of this fact, the closure of a convex set of operators in the WOT is the same as the closure of that set in the SOT.

It follows from the polarization identity that a net converges to in SOT if and only if in WOT.

Weak-star operator topology

The predual of B(H) is the trace class operators C1(H), and it generates the w*-topology on B(H), called the weak-star operator topology or σ-weak topology. The weak-operator and σ-weak topologies agree on norm-bounded sets in B(H).

A net {Tα} ⊂ B(H) converges to T in WOT if and only Tr(TαF) converges to Tr(TF) for all finite-rank operator F. Since every finite-rank operator is trace-class, this implies that WOT is weaker than the σ-weak topology. To see why the claim is true, recall that every finite-rank operator F is a finite sum

So {Tα} converges to T in WOT means

Extending slightly, one can say that the weak-operator and σ-weak topologies agree on norm-bounded sets in B(H): Every trace-class operator is of the form

where the series converges. Suppose and in WOT. For every trace-class S,

by invoking, for instance, the dominated convergence theorem.

Therefore every norm-bounded closed set is compact in WOT, by the Banach–Alaoglu theorem.

Other properties

The adjoint operation TT*, as an immediate consequence of its definition, is continuous in WOT.

Multiplication is not jointly continuous in WOT: again let be the unilateral shift. Appealing to Cauchy-Schwarz, one has that both Tn and T*n converges to 0 in WOT. But T*nTn is the identity operator for all . (Because WOT coincides with the σ-weak topology on bounded sets, multiplication is not jointly continuous in the σ-weak topology.)

However, a weaker claim can be made: multiplication is separately continuous in WOT. If a net TiT in WOT, then STiST and TiSTS in WOT.

SOT and WOT on B(X,Y) when X and Y are normed spaces

References

See also

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