1990 United States House of Representatives elections in Virginia
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1990 House elections in Virginia
All 10 Virginia seats to the United States House of Representatives | |||||||||||||||||||||||||||||||||||||
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The 1990 United States House of Representatives elections in Virginia were held on November 6, 1990 to determine who will represent the Commonwealth of Virginia in the United States House of Representatives. Virginia had ten seats in the House, apportioned according to the 1980 United States Census. Representatives are elected for two-year terms.
| United States House of Representatives elections in Virginia, 1990[1] | |||||
|---|---|---|---|---|---|
| Party | Votes | Percentage | Seats | +/– | |
| Democratic | 662,800 | 57.49% | 6 | +1 | |
| Republican | 410,941 | 35.64% | 4 | -1 | |
| Independents/Write-ins | 79,133 | 6.86% | 0 | - | |
| Totals | 1,152,874 | 100.00% | 10 | - | |
References
See also
| U.S. Senate |
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| U.S. House |
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| State governors |
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| Attorneys General | |
| State legislatures |
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| Mayors | |
| States generally |
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