1998 Maryland Attorney General election
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 County results Curran: 50–60% 60–70% 70–80% 80–90% Rappaport: 50–60% 60–70% | |||||||||||||||||
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The 1998 Maryland attorney general election was held on November 3, 1998, in order to elect the attorney general of Maryland. Democratic nominee and incumbent attorney general J. Joseph Curran Jr. defeated Republican nominee Paul H. Rappaport.[1]
Results
On election day, November 3, 1998, Democratic nominee J. Joseph Curran Jr. won re-election by a margin of 391,225 votes against his opponent Republican nominee Paul H. Rappaport, thereby retaining Democratic control over the office of attorney general. Curran was sworn in for his fourth term on January 3, 1999.[2]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | J. Joseph Curran Jr. (incumbent) | 922,655 | 63.45 | |
| Republican | Paul H. Rappaport | 531,430 | 36.55 | |
| Total votes | 1,454,085 | 100.00 | ||
| Democratic hold | ||||
References
- ↑ "1998 Attorney General General Election Results - Maryland". uselectionatlas.org. February 24, 2011. Retrieved 2024-10-23.
- ↑ "MD Attorney General". ourcampaigns.com. December 8, 2008. Retrieved 2024-10-23.
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See also: Political party strength in Maryland | |||||||||||||||||||
